## GENERAL ADDITION – VEDIC MATHEMATICS SERIES: 1

Vedic Mathematics!

What is it? A tool? A topic? Or an entirely different subject??

Well, the answer would be “none of these.”

India is country that has produced extremely proud set of Scientists, Mathematicians, Astrologers, Doctors, and many more. Sushruta, father of Plastic Surgery, has been born in India. Aryabhatta, the great mathematician and astronomer was born in India in 476 AD. This list is vast, and beyond our scope of knowledge.

Their contribution has been immense to the world. Honestly, none of us can explain all about the vedas, but MyPerfectice team has decided to bring you some of the most essential elements of it, starting from the Vedic Mathematics. It contains lots and lots of theories and formulae, but we’ll concentrate only on a few which are essential, and will help you in any entrance exam.

In the very first blog of Vedic Mathematics Series, we’ll focus entirely on the ADDITION OF NUMBERS:-

ADDITION BY ADDING NUMBERS FROM LEFT TO RIGHT
Generally we add numbers starting from right, and if the sum exceeds 10, we carry the tens digit to the immediate left in the series, and proceed. But in this method, we’ll do the opposite. To understand it, we’ll take the example of two 3-digit numbers (423 + 222)

Steps:-

1. First, we add the leftmost digits(HUNDREDS PLACE VALUE here) in both numbers, i.e., 4 and 2. On adding these two, we get 6(4+2). [We get 600]
2. Next, we add the digits on the immediate right(TENS PLACE VALUE here) of both the given numbers. In above case, it is 2 and 2. It becomes 4(2+2). [We get 40]
3. Then, we add the digits immediate right to it(UNITS PLACE VALUE here) of both the numbers. In above case, it is 3 and 2. So, we get 5(3+2). [We get 5]
4. Now, we’ll add up all the final values which we have attained, i.e.,
600 + 40 + 5 = 645 which is the final answer.

For more details, refer to the following example.

ADDITION BY ROUNDING OF NUMBERS

Caution: THIS METHOD IS TO BE USED ONLY WHEN GIVEN NUMBERS ARE CLOSE TO ANY SUITABLE NUMBER TO WHICH THEY CAN BE ROUNDED OFF.

To understand it, we’ll take the example of two 3-digit numbers(622 + 789)

Steps:-

1. First, take one number, say, 622. Find the closest number to it which is easier to round off (600 or 620 in this case). Let’s solve it by using both techniques.
2. Then, take another number and do the same. (The numbers we get here are 800 and 790). We’ll take both one by one.

By using 600 and 800:-

1. We split the number in sum of 2 numbers. So, the two numbers become 600+22 and 800-11.
2. Then, we add the rounded off numbers together. (600+800=1400)
3. After that, we take the other term in both the numbers and add them. (22-11=11)(Since, 22 is added in one and 11 is subtracted in other.)
4. We add the numbers obtained from above processes(1400+11=1411). This is the required answer.

By using 620 and 790:-

1. We split the number in sum of 2 numbers. So, the two numbers become 620+2 and 790-1.
2. Then, we add the rounded off numbers together. (620+790=1410)
3. After that, we take the other term in both the numbers and add them. (2-1=1)(Since, 2 is added in one and 1 is subtracted in other.)
4. We add the numbers obtained from above processes(1410+1=1411). This is the required answer.

For more details, refer to the following example.

Though, it may look tough and lengthy in the first look, but once you have practiced it enough. It takes only 5-6 seconds to do the summation. This method can be extended up to any amount of numbers of any length, can can be very accurate. Sometimes in MCQs, you need only approximate answers, and this method has proved it be very useful there.
For your Practice, here are a few question that you can try :
1) 345+456
2) 765+375
3) 890+394
4) 817+4567
5) 85934+75830
And that marks the end of the first blog in Vedic Mathematics Series.
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